BIZOMAT MAKEOS · Hydraulics

Cylinder Meter-Out Speed Control (Orifice, Intensification, Heat)

What meter-out orifice sets this cylinder to the speed I want under its load, how high does the rod-side pressure rise, and how much heat does the control make?

Meter-out flow control of a double-acting cylinder extending against a resisting or overrunning load: cap-side and annulus areas, cap-side flow for the speed against pump flow, rod-side (back) pressure from the force balance including intensification, the orifice diameter that passes the rod-side flow at that pressure drop (as the orifice flow tool), heat generated in the orifice and over the relief valve, and the rod-side pressure against its rating.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
BoremmCylinder bore.
Rod diametermmRod diameter.
Supply (relief) pressurebarPressure on the cap side (the relief setting holds it there with meter-out control).
Load (positive resists, negative overruns)kNLoad on the rod: positive when it resists extension, negative when it pulls the rod out.
Extend speed wantedm/sExtension speed wanted.
Pump flowL/minPump flow available.
Orifice discharge coefficientDischarge coefficient of the orifice or valve (about 0.6–0.7).
Oil densitykg/m³Oil density.
Rod-side pressure ratingbarPressure rating of the rod-side seals, cylinder and valve.

What each input means

Open an input to see what it is, its units, the worked example and the common mistakes, with a small diagram.

What this means: Bore
Illustration: BoreA circle with a line straight through its centre from edge to edge, marking the diameter Bore.Dmeasured acrossthe centreExample: 63 mmBore
What it is
The inside diameter of the cylinder barrel, which sets the cap-side area the supply pressure acts on.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 1000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 63 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
What this means: Rod diameter
Illustration: Rod diameterA circle with a line straight through its centre from edge to edge, marking the diameter Rod diameter.dmeasured acrossthe centreExample: 36 mmRod diameter
What it is
The diameter of the piston rod. The annulus area on the rod side is the bore area less the rod area.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 1000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 36 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
A larger rod shrinks the annulus and raises rod-side pressure (intensification).
Get it right
It must be smaller than the bore, or the tool stops.
What this means: Supply (relief) pressure
Illustration: Supply (relief) pressureA pressure gauge whose needle moves with Supply (relief) pressure; the needle follows the value you type.p₁Example: 100 barSupply (relief) pressure
What it is
The pressure held on the cap side during extension. With meter-out control the relief valve holds the supply at its setting.
Units and format
Enter a number in bar: bar (1 bar = 100 kPa). The form accepts 0.000001 bar to 700 bar. Required: the tool does not calculate until every input is valid.
Example
The form opens with 100 bar as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
A higher supply pressure raises the rod-side pressure and the heat over the relief.
Get it right
Enter gauge pressure at the cylinder port.
What this means: Load (positive resists, negative overruns)
Illustration: Load (positive resists, negative overruns)A block with an arrow pushing on it; the arrow is the force Load (positive resists, negative overruns).FExample: 15 kNLoad (positive resists, negative overruns)
What it is
The external load on the rod during extension. Positive when it resists the motion, negative when it pulls the rod out (an overrunning load).
Units and format
Enter a number in kN: kilonewtons (1 kN = 1000 N). The form accepts -10000 kN to 10000 kN. Required: the tool does not calculate until every input is valid.
Example
The form opens with 15 kN as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Each extra kN of resisting load lowers the rod-side pressure.
Get it right
An overrunning load must be entered as negative; it raises the rod-side pressure.
What this means: Extend speed wanted
Illustration: Extend speed wantedA marker moving along a track; Extend speed wanted is the distance it covers per unit of time.vdistance ÷ timeExample: 0.1 m/sExtend speed wanted
What it is
The speed you want the rod to extend at, controlled by the meter-out orifice on the rod side.
Units and format
Enter a number in m/s: metres per second. The form accepts 0.000001 m/s to 10 m/s. Required: the tool does not calculate until every input is valid.
Example
The form opens with 0.1 m/s as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Flows rise in proportion; the orifice area needed grows in proportion too.
Get it right
Metres per second: 100 mm/s is 0.1 m/s.
What this means: Pump flow
Illustration: Pump flowA pipe with liquid or gas moving through it; Pump flow is the volume that passes per unit of time.Q_pExample: 25 L/minPump flow
What it is
The flow the pump delivers. Any flow beyond what the cap side takes passes over the relief valve as heat.
Units and format
Enter a number in L/min: litres per minute. The form accepts 0.000001 L/min to 10000 L/min. Required: the tool does not calculate until every input is valid.
Example
The form opens with 25 L/min as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Extra pump flow above the cylinder’s need adds relief heat in proportion.
Get it right
Use the delivered flow at working pressure, not the nameplate displacement.
What this means: Orifice discharge coefficient
Illustration: Orifice discharge coefficientTwo bars: a base value and the same value multiplied by Orifice discharge coefficient, the factor.base valuewith factorC_dExample: 0.62Orifice discharge coefficient
What it is
The discharge coefficient of the control orifice or flow valve: the ratio of real to ideal flow through it, from the valve maker or orifice data.
Units and format
Enter a plain number with no unit. The form accepts 0.3 to 1. Required: the tool does not calculate until every input is valid.
Example
The form opens with 0.62 as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
A higher coefficient lets a smaller orifice pass the same flow.
Get it right
It is a dimensionless ratio, not a flow or a size.
What this means: Oil density
Illustration: Oil densityA cube of material: density Oil density is its mass divided by the volume it fills.massvolumeρExample: 870 kg/m³Oil density
What it is
The density of the hydraulic oil at operating temperature, from the oil data sheet.
Units and format
Enter a number in kg/m³: kilograms per cubic metre. The form accepts 0.000001 kg/m³ to 1500 kg/m³. Required: the tool does not calculate until every input is valid.
Example
The form opens with 870 kg/m³ as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
Enter kilograms per cubic metre, not kilograms per litre.
What this means: Rod-side pressure rating
Illustration: Rod-side pressure ratingA pressure gauge whose needle moves with Rod-side pressure rating; the needle follows the value you type.pExample: 250 barRod-side pressure rating
What it is
The lowest pressure rating among the rod-side seals, cylinder and meter-out valve. The intensified rod-side pressure is checked against it.
Units and format
Enter a number in bar: bar (1 bar = 100 kPa). The form accepts 0.000001 bar to 1000 bar. Required: the tool does not calculate until every input is valid.
Example
The form opens with 250 bar as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
Take the rating from the maker of each component and use the lowest.

Method and formulas

  1. A₁ = π D² ÷ 4, A₂ = A₁ − π d² ÷ 4; Q₁ = A₁ v, Q₂ = A₂ v.
  2. Force balance p₁ A₁ = F + p₂ A₂, so p₂ = (p₁ A₁ − F) ÷ A₂ (an overrunning load raises it above p₁ A₁ ÷ A₂).
  3. Orifice area A₀ = Q₂ ÷ [C_d √(2 p₂ ÷ ρ)] with the tank at zero pressure (as the orifice flow tool).
  4. Heat = p₂ Q₂ (orifice) + p₁ (Q_p − Q₁) (relief).
  5. Example: 0.1 m/s against 15 kN needs a 1.7999 mm orifice; the rod side runs at 77.035 bar and the circuit makes 2.6667 kW of heat.

Limitations

  • Sharp-edged orifice, turbulent flow; a pressure-compensated flow control holds speed as the load changes.
  • Line and valve losses are not included.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Size a fixed orifice or set a flow control for a cylinder speed
  • Check rod-side pressure with a meter-out circuit
  • Estimate heat from speed control

Who it is for

  • Hydraulic engineers
  • Machine designers
  • Maintenance engineers

What you get

  • Areas, flows and pump check
  • Rod-side pressure and intensification
  • Orifice diameter and heat

Interpreting the result

  • Meter-out holds overrunning loads but intensifies rod-side pressure: check the rod seals when the load reverses.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 3024–3027, 352–368. Topic reference; no source tables or recommended settings are reproduced.

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