BIZOMAT MAKEOS · Springs

Disc (Belleville) Spring Load and Stress

What force and stress does this disc spring, or stack, give at a deflection?

Load, flat load and top inner-edge stress of a disc (Belleville) spring by the Almen–László method, and the force and travel of series and parallel stacks.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
Outside diametermmOutside diameter from the catalogue.
Inside diametermmInside diameter from the catalogue.
ThicknessmmDisc thickness.
Cone height h₀ (free height − thickness)mmUnloaded height l₀ minus thickness t, from the catalogue.
Elastic modulusGPaElastic modulus of the spring steel.
Poisson’s ratioPoisson’s ratio (about 0.3).
Deflection of one discmmDeflection of a single disc at the working position (no more than h₀).
Discs in series (alternating)discsNumber of single discs (or parallel sets) stacked in alternating directions.
Discs in parallel (nested)discsNumber of discs nested in the same direction in each set.

What each input means

Open an input to see what it is, its units, the worked example and the common mistakes, with a small diagram.

What this means: Outside diameter
Illustration: Outside diameterA circle with a line straight through its centre from edge to edge, marking the diameter Outside diameter.Demeasured acrossthe centreExample: 50 mmOutside diameter
What it is
The outside diameter of the disc (Belleville) spring, from the catalogue or drawing.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 10000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 50 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
It must be larger than the inside diameter.
What this means: Inside diameter
Illustration: Inside diameterA circle with a line straight through its centre from edge to edge, marking the diameter Inside diameter.Dimeasured acrossthe centreExample: 25.4 mmInside diameter
What it is
The inside (bore) diameter of the disc spring, from the catalogue or drawing.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 10000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 25.4 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
It must be smaller than the outside diameter.
What this means: Thickness
Illustration: ThicknessThe cross-section of a plate or wall with a dimension across its thickness, marking Thickness.tsection through the materialExample: 2 mmThickness
What it is
The thickness of the disc spring material.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 1000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 2 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
The force rises steeply with thickness.
Get it right
Use the catalogue thickness; for discs with contact flats this model does not apply.
What this means: Cone height h₀ (free height − thickness)
Illustration: Cone height h₀ (free height − thickness)A block with a vertical dimension line from its base to its top, marking the height Cone height h₀ (free height − thickness).h₀Example: 1.4 mmCone height h₀ (free height − thickness)
What it is
The free cone height of one disc: its unloaded overall height minus the material thickness. It is how far the disc can deflect before it is flat.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 1000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1.4 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
Do not enter the overall free height; subtract the thickness first.
What this means: Elastic modulus
Illustration: Elastic modulusA stress against strain graph whose straight starting slope is the stiffness value Elastic modulus.stressstrainEExample: 206 GPaElastic modulus
What it is
The elastic modulus (Young’s modulus) of the disc spring steel, from the maker or material data.
Units and format
Enter a number in GPa: gigapascals (1 GPa = 1000 MPa). The form accepts 0.000001 GPa to 1000 GPa. Required: the tool does not calculate until every input is valid.
Example
The form opens with 206 GPa as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Force and stress rise in proportion to it.
Get it right
Enter GPa, not MPa: 1 GPa is 1000 MPa.
What this means: Poisson’s ratio
Illustration: Poisson’s ratioA number line with a marker at the value of Poisson’s ratio, between its lowest and highest accepted values.00.5νExample: 0.3Poisson’s ratio
What it is
Poisson’s ratio of the disc spring material, from the maker or material data.
Units and format
Enter a plain number with no unit. The form accepts 0 to 0.5. Required: the tool does not calculate until every input is valid.
Example
The form opens with 0.3 as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
It is a dimensionless ratio, not a percentage.
What this means: Deflection of one disc
Illustration: Deflection of one discA bar with a dimension line and arrows from one end to the other, marking the length Deflection of one disc.sExample: 1.05 mmDeflection of one disc
What it is
How far one single disc is compressed at the working position, measured from its free height.
Units and format
Enter a number in mm: millimetres. The form accepts 0 mm to 1000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1.05 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
Enter the deflection of one disc, not of the whole stack; it cannot exceed the free cone height.
What this means: Discs in series (alternating)
Illustration: Discs in series (alternating)A row of identical items being counted; Discs in series (alternating) is how many there are.nₛExample: 1 discsDiscs in series (alternating)
What it is
The number of single discs, or nested sets, stacked face to face in alternating directions. Their deflections add.
Units and format
Enter a number in discs: discs. The form accepts 1 discs to 1000 discs. Use a whole number. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1 discs as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Stack travel rises in proportion; force is unchanged.
Get it right
It multiplies the stack travel, not the force.
What this means: Discs in parallel (nested)
Illustration: Discs in parallel (nested)A row of identical items being counted; Discs in parallel (nested) is how many there are.nₚExample: 1 discsDiscs in parallel (nested)
What it is
The number of discs nested in the same direction within each set. Their forces add.
Units and format
Enter a number in discs: discs. The form accepts 1 discs to 100 discs. Use a whole number. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1 discs as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
The stack force rises in proportion; travel is unchanged.
Get it right
Friction between nested discs is ignored, so the real loading force is higher and the unloading force lower.

Method and formulas

  1. δ = De ÷ Di; K₁ = (1/π)((δ − 1)/δ)² ÷ ((δ + 1)/(δ − 1) − 2/ln δ).
  2. F = 4E ÷ (1 − ν²) × t⁴ ÷ (K₁De²) × (s/t) × [(h₀/t − s/t)(h₀/t − s/2t) + 1].
  3. σI = −4E ÷ (1 − ν²) × t² ÷ (K₁De²) × (s/t) × [K₂(h₀/t − s/2t) + K₃], with K₂ = (6/π)((δ − 1)/ln δ − 1)/ln δ and K₃ = (3/π)(δ − 1)/ln δ.
  4. Stack force = F × parallel count (friction neglected); stack travel = s × series count.
  5. Example: the default disc gives 4,762.1 N at 1.05 mm deflection and 5,897.9 N at flat.

Limitations

  • Discs without contact flats; friction in parallel stacks raises loading force and lowers unloading force.
  • Fatigue needs the tensile stresses at the lower edges (σII, σIII) and the maker’s fatigue diagrams.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Size disc stacks for bolted joints, clutches and valves
  • Check load at a set deflection
  • Compare series and parallel stacking

Who it is for

  • Design engineers
  • Spring buyers
  • Maintenance engineers

What you get

  • Force of one disc and of the stack
  • Force at flat
  • Top inner-edge stress (σOM and σI)
  • Stack travel

Interpreting the result

  • Keep the working deflection at or below about 75% of h₀ for a predictable, near-linear characteristic.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 350–359. Topic reference; no source tables or recommended settings are reproduced.
  • EN 16983:2016 Disc springs — Quality specifications — Dimensions; EN 16984:2016 Disc springs — Calculation

Learn the Concepts Behind This Tool

These BIZOMAT Library readings explain the method this tool uses, with worked examples.

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Open the Disc (Belleville) Spring Load and Stress calculator