BIZOMAT MAKEOS · Pneumatics

Velocity and Flow of Escaping Compressed Air

How fast and how much air escapes from this tank through a hole or nozzle?

Theoretical velocity of air escaping adiabatically from a large container by the handbook formula, the velocity actually reached at a plain orifice (limited to sonic when the flow chokes), and the mass and free-air flow through an orifice of given size.

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How this tool works

Inputs, units and where to find them

InputUnitTypical source
Tank pressure (gauge)barGauge pressure in the container.
Outside pressure (absolute)barAbsolute pressure outside the orifice (atmospheric is 1.01325 bar).
Air temperature in the tank°CAir temperature in the container.
Ratio of specific heatsRatio of specific heats: 1.4 for air (the handbook uses 1.41).
Orifice diametermmDiameter of the hole or nozzle.
Discharge coefficientDischarge coefficient of the orifice (sharp-edged about 0.6–0.65, rounded nozzle up to about 0.97; confirm for yours).

What each input means

Open an input to see what it is, its units, the worked example and the common mistakes, with a small diagram.

What this means: Tank pressure (gauge)
Illustration: Tank pressure (gauge)A pressure gauge whose needle moves with Tank pressure (gauge); the needle follows the value you type.p₁Example: 6 barTank pressure (gauge)
What it is
The pressure of the air inside the tank or line as read on a gauge, above atmospheric. The tool adds standard atmospheric pressure to get the absolute value.
Units and format
Enter a number in bar: bar (1 bar = 100 kPa). The form accepts 0.000001 bar to 1000 bar. Required: the tool does not calculate until every input is valid.
Example
The form opens with 6 bar as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Once the flow is choked, mass flow rises in proportion to the absolute tank pressure while the velocity stays sonic.
Get it right
Gauge pressure: do not add atmospheric pressure yourself. 1 bar = 100 kPa.
What this means: Outside pressure (absolute)
Illustration: Outside pressure (absolute)A pressure gauge whose needle moves with Outside pressure (absolute); the needle follows the value you type.p₂Example: 1.01325 barOutside pressure (absolute)
What it is
The absolute pressure of the space the air escapes into, usually the local atmosphere; with the tank pressure it sets the ratio that decides whether the flow chokes.
Units and format
Enter a number in bar: bar (1 bar = 100 kPa). The form accepts 0.000001 bar to 1000 bar. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1.01325 bar as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
Absolute, not gauge: the standard atmosphere is 1.01325 bar, and local pressure is lower at altitude.
What this means: Air temperature in the tank
Illustration: Air temperature in the tankA thermometer whose level rises with Air temperature in the tank; the level follows the value you type.TExample: 21 °CAir temperature in the tank
What it is
The temperature of the compressed air inside the tank, upstream of the orifice; it is converted to kelvin for the velocity and flow equations.
Units and format
Enter a number in °C: degrees Celsius. The form accepts -50 °C to 500 °C. Required: the tool does not calculate until every input is valid.
Example
The form opens with 21 °C as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
The escape velocity rises with the square root of the absolute temperature.
What this means: Ratio of specific heats
Illustration: Ratio of specific heatsTwo wheels of different sizes linked together; Ratio of specific heats compares one with the other.kExample: 1.4Ratio of specific heats
What it is
The ratio of the gas’s specific heat at constant pressure to its specific heat at constant volume (cp ÷ cv), which governs how it cools as it expands.
Units and format
Enter a plain number with no unit. The form accepts 1.01 to 1.7. Required: the tool does not calculate until every input is valid.
Example
The form opens with 1.4 as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Get it right
Take it from gas property tables for the gas actually being released.
What this means: Orifice diameter
Illustration: Orifice diameterA circle with a line straight through its centre from edge to edge, marking the diameter Orifice diameter.dmeasured acrossthe centreExample: 2 mmOrifice diameter
What it is
The diameter of the hole, leak or nozzle the air escapes through, at its narrowest point.
Units and format
Enter a number in mm: millimetres. The form accepts 0.000001 mm to 1000 mm. Required: the tool does not calculate until every input is valid.
Example
The form opens with 2 mm as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Mass flow and free-air flow rise with the square of the diameter; the velocity does not change.
What this means: Discharge coefficient
Illustration: Discharge coefficientTwo bars: a base value and the same value multiplied by Discharge coefficient, the factor.base valuewith factorC_dExample: 0.65Discharge coefficient
What it is
The ratio of the actual flow through the orifice to the ideal flow, allowing for contraction of the jet and friction at the edge; it depends on the orifice shape.
Units and format
Enter a plain number with no unit. The form accepts 0.000001 to 1. Required: the tool does not calculate until every input is valid.
Example
The form opens with 0.65 as a worked example. It is an illustration, not a recommended value: replace it with your own figure.
Effect on the result
Mass flow and free-air flow rise in proportion.
Get it right
It reduces the flow only, not the velocity; take it from orifice test data or a flow handbook for your hole shape.

Method and formulas

  1. Handbook (adiabatic): v₂ = √{2 k ÷ (k − 1) × R T × [1 − (p₂ ÷ p₁)^((k−1)/k)]}, with R = 287 J/kg·K.
  2. When p₂ ÷ p₁ is below (2 ÷ (k + 1))^(k/(k−1)) ≈ 0.53 the orifice flow chokes and the velocity there is sonic: √(2 k R T ÷ (k + 1)).
  3. Mass flow through the orifice uses the compressible orifice equations; free-air flow at 1.01325 bar and 20 °C.
  4. Example: air at 6 bar gauge through a 2 mm hole escapes at 313.86 m/s and 168.16 L/min of free air.

Limitations

  • Large container, steady flow, ideal gas.
  • Higher pressure does not raise the orifice velocity once choked; it raises the mass flow.
  • Example values are illustrations. Replace them with values for your actual task.

Typical uses

  • Estimate air loss through a leak or blow-off nozzle
  • Check whether a vent is choked
  • Size an orifice for a purge flow

Who it is for

  • Compressed-air engineers
  • Maintenance engineers
  • Process engineers

What you get

  • Escape velocity
  • Whether the flow is choked
  • Mass and free-air flow

Interpreting the result

  • Use the free-air flow with the compressor’s specific power to price a leak.

References

  • Machinery’s Handbook, 29th edition (Industrial Press, 2012), printed pp. 3037–3038. Topic reference; no source tables or recommended settings are reproduced.

Learn the Concepts Behind This Tool

These BIZOMAT Library readings explain the method this tool uses, with worked examples.

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